4x^2-32x=38

Solution for 4x^2-32x=38 equation:

4x^2-32x=38

We move all terms to the left:

4x^2-32x-(38)=0

a = 4; b = -32; c = -38;
Δ = b2-4ac
Δ = -322-4·4·(-38)
Δ = 1632
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1632}=\sqrt{16*102}=\sqrt{16}*\sqrt{102}=4\sqrt{102}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-4\sqrt{102}}{2*4}=\frac{32-4\sqrt{102}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+4\sqrt{102}}{2*4}=\frac{32+4\sqrt{102}}{8}
$